Question

Can someone check my math answers?

Answer 1

Ill try

Answer 2

Do you know how to find the mean, median, mode and range?

Answer 3

Mean is when all of the numbers are added together and divided by the amount of numbers their are?

Answer 4

Nvm, X_X

Give me a sec

Answer 5

Sorry.. And Okay.

Answer 6

The first one is wrong

Answer 7

I had a feeling, its D?

Answer 8

Median is the middle number, set it up in order and find the middle number. If it's even then add the TWO middle numbers and divide by 2

Answer 9

Yes d

Answer 10

Thank you. And Is number 2 wrong as well?

Answer 11

As for the last one there's a method to check, give me a second to calculate it

Answer 12

Great, Thank you.

Answer 13

Since outliers in a data set stand out, you can identify them just by looking at the data. However, outliers are defined according to the interquartile range (IQR).

first you have to find the IQR.
multiply the IQR by 1.5.
subtract this number from Q1 and add this number to Q3 to find the limits for the outliers.

The Lower Limit: Outlier < Q1 – 1.5(IQR)
And The Upper Limit: Outlier > Q3 + 1.5(IQR)

Answer 14

Do you know how to find the IQR?

Answer 15

Nope :/

Answer 16

Well I mean, i do, just i don't really have a clear understanding on it.

Answer 17

internet derped X_X

IQR = Q3 - Q1

First find q1 and q3, know how to?

Answer 18

Sorry, Lol. Um, can you help me work through the whole thing?

Answer 19

sure ^_^

Answer 20

Thanks so much. Im Failing my math class, and need all the help i can get.

Answer 21

First put it in order from least to greatest.

13,13,13,15,21,23,25,37 ... Tell me if I missed any :p

There are 8 (even so) grab half.

{13,13,13,15} ---- and ---- { 21,23,25,37 }

So 13 + 13 = 26 / 2 = 13, therefore the Q1 is 13.

Q3 is 23 + 25 = 48 / 2 = 24. This makes sense because 24 is the middle number between 23 and 25!

Now that you have the q1 and q3.

IQR = q3 - q1

So, 24 - 13 = 11

Now, The Lower Limit: Outlier < Q1 – 1.5(IQR)

outlier < 13 - 1.5(11)
< 13 -16.5
< -3.5

So any outlier will be anything below -3.5

Answer 22

Outlier > Q3 + 1.5(IQR)
> 24 + 1.5(11)
> 24 + 16.5
> 40.5

Anything above 40.5 is an outlier. There isn't so there are no outliers

Answer 23

So the answer is either A or D?

Answer 24

Hm, i didn't find any outliers ._. let's continue onto the next part, we'll get back to it

Answer 25

Okay.

Answer 26

Now you tell me xD what's the outlier of the data

Answer 27

I thought it was 13? Lol.

Answer 28

13,13,13,15,21,23,25,37 = 20 not 13

add them up and divide by 8

Answer 29

Oh Okay, Give me a second.

Answer 30

17.7?

Answer 31

No, I just gave you the mean lol

Answer 32

http://prntscr.com/32kena

Answer 33

I'm confused? You told me to add all those up, and divide by 8, and i did so.

Answer 34

\[\frac{ 13 + 13 + 13 + 15 + 21 + 23 + 25 + 37 }{ 8 }\]

Answer 35

I got 190, then i divided it by 8.

Answer 36

190? You should get 160

Answer 37

Thats what i meant lol xD

Answer 38

k so the mean is 20 onto the third, it says without the outlier. I don't see any outlier ._. that's the thing.

Thinking outside the box ;) look at how the mean is the second place value or the B. Including all of the numbers. Only one of them has 20 in the b section. suppose you didn't know the formula for the outliers you would have to guess and based on just looking. I would also say 37 is an outlier, so excluding 37, add all of them again and divisive by 7. Don't include 37.

Answer 39

Maybe @mathmale can shine some light on your doubt >.> id that made any sense at all lol xD

I'm going to say the correct answer is B.

Answer 40

If*

Answer 41

@tHe_FiZiCx99 : Many thanks for the referral!

@LaLaLawson : I don't want to repeat what you already know, so ask you to tell me what you're still unsure of and/or need to find. I see y ou're working on the 2nd question now.

Answer 42

Sure, no problem! @mathmale

Answer 43

Sorry My Internet went weird. Lol. Thank you.

Answer 44

OK: Please tell me as best you can what you want to know now.

Answer 45

I see you need to identify the one outlier. How would you go about doing that?

Answer 46

I also have someone helping me on another site, and i understand now, i have a few other questions that i was wondering if you could check?

Answer 47

*Cough* was I right?

Answer 48

Yes. Haha Thank you.

Answer 49

♦o♦ You're welcome :>

Answer 50

Stem and leaf plots are fun, they aren't that hard >.>

Answer 51

If you'd point out which part of your work you want feedback on, sure. But I'd prefer not to go through an entire problem and give you a "right" or "wrong" response.

If you're tied up on another site, why not finish that first and return to this one with your question?

Answer 52

It's 4pm, sorry I have to get off :/

Maybe if I'm on later :P

Answer 53

Bye, Fizic!

Answer 54

Bye Mathmale!!