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I just need a little help please. I have got the answer almost.
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\[\cos (x+45)- \sqrt{2}\sin x=2\]
I solved the equation and got the answer of x= -45.0 degrees. The question says give answer in the range 0<x<360. -45.0 means 315 degrees. But there is a second value of x=261.9. How do I get that?
I haven't figured out how to get to the other answer, but I can tell you that it is \[x = -\cos^{-1}(-\frac{1}{5\sqrt{2}})\]
I figured it out. The values of cos^-1 in 1st quadrant gives x=-45.0, and in the third quadrant, would give me 261.9. Thankyou.
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