Question

whats the standard form of a line passing through the points (2,-3) and (4,2)

Answer 1

you need to first find the slope by using the slope formula
slope(m) = (y2 - y1) / (x2 - x1)
(2,-3) x1 = 2 and y1 = -3
(4,2) x2 = 4 and y2 = 2
now we sub
slope(m) = (2 - (-3) / (4 - 2)

can you finish and find the slope ?

Answer 2

let me know when your ready to participate :)

Answer 3

@texaschic101 gonna see if you recall what standard form looks like :)

Answer 4

Ax + By = C is standard form

Answer 5

hold on

Answer 6

very good ;)

Answer 7

you figure the slope out yet ??

Answer 8

no

Answer 9

slope(m) = (2 - (-3) / (4 - 2)
slope(m) = (2 + 3) / 2
slope(m) = 5/2
you understand so far ?

Answer 10

yes

Answer 11

no we will use y = mx + b form....

slope(m) = 5/2
you can use either of your points...I will use (4,2) x = 4 and y = 2
now we sub and solve for b
y = mx + b
2 = 5/2(4) + b
2 = 10 + b
2 - 10 = b
-8 = b
so our equation is : y = 5/2x - 8

still with me or do you have any questions ?

Answer 12

now we need to turn this into Ax + By = C

y = 5/2x - 8 -- multiply the entire equation by 2
2y = 5x - 16 -- subtract 5x from both sides
-5x + 2y = -16 -- multiply by -1 to make x positive
5x - 2y = 16 ==> standard form