Question

lim (1+logx-x)/(1-2x+x^2) = ?
x->1

Answer 1

\[\lim_{x \rightarrow 1} \frac{ 1+logx - x }{ 1-2x+x^2 }\]

Answer 2

now expand log x

Answer 3

log x, expansion? what is it ? can you please tell me

Answer 4

okk leave it

Answer 5

u knw l'hopital rule ??

Answer 6

differentiate numerator and denominator seperatly

Answer 7

Yes I did that and got -1/2 as the answer. But it is not there in the options given.

Answer 8

\[\lim_{x \rightarrow 1} \frac{ 0+\frac{ 1 }{ x } -1}{ 0-2+2x }\]

Answer 9

its a silly Q but u type the Q correctly??

Answer 10

it is log x or ln x

Answer 11

Its lnx

Answer 12

Please provide the final answer to it. I got it -1/2.

Answer 13

its coming -1/2 only

Answer 14

Ok, with the expansion too I am getting -1/2. So may be its the mistake of the options given for the question. Thank you very much.