A spinner is divided into sections shaded either black or gray. The probability that the spinner will stop on a black section is 20 percent.
What is the probability that the spinner will stop on a gray section?
A.
20%
B.
40%
C.
60%
D.
80%
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OpenStudy (anonymous):
kc_kennylau
OpenStudy (kc_kennylau):
1 - 20%
OpenStudy (kc_kennylau):
Because it's either black or gray
OpenStudy (kc_kennylau):
So P(black) + P(gray) = 1
OpenStudy (kc_kennylau):
Get it?
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OpenStudy (anonymous):
no
OpenStudy (kc_kennylau):
P(something) means probability of something
OpenStudy (kc_kennylau):
P(A or B) = P(A) + P(B)
P(A and B) = P(A) * P(B)
OpenStudy (kc_kennylau):
These two formulas will be very useful
OpenStudy (kc_kennylau):
It's either black or gray, so P(black or gray) = 1 because it must happen
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OpenStudy (kc_kennylau):
Anything that "must happen" will have a probability of 1
OpenStudy (kc_kennylau):
Get it?
OpenStudy (kc_kennylau):
Do you understand why P(black or gray)=1
OpenStudy (anonymous):
yes
OpenStudy (kc_kennylau):
P(black or gray)=1
Therefore P(black) + P(gray) = 1
Do you understand this
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OpenStudy (anonymous):
kinda
OpenStudy (anonymous):
those are complimentary events.
OpenStudy (kc_kennylau):
Because P(A or B) = P(A)+P(B)
OpenStudy (kc_kennylau):
Therefore P(black or gray) = P(black) + P(gray)
OpenStudy (kc_kennylau):
Therefore P(black) + P(gray) = 1
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OpenStudy (kc_kennylau):
Now you have P(black)=20%
OpenStudy (kc_kennylau):
Substitute P(black)=20% to P(black)+P(gray)=1
OpenStudy (kc_kennylau):
Understand?
OpenStudy (anonymous):
i think
OpenStudy (kc_kennylau):
Then do it
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OpenStudy (anonymous):
probability of wheel to stop at black is 20%. so what if doesnt stop on black .. it stops on grey .. it means its probability become rest of 100. that is 100-20 = 80
OpenStudy (anonymous):
ohhh now i understand
OpenStudy (kc_kennylau):
Glad you understand, because we gave no explanation to the questions before this
OpenStudy (anonymous):
so the ans id 80
OpenStudy (kc_kennylau):
Yes
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OpenStudy (anonymous):
@kc_kennylau tried very hard to make you @72595210002 understand .. i give him my medal.