Question

A 13.5 g block of metal, initially at 124.4 °C, is placed in 25.0 g of water, initially at 24.9 °C. At equilibrium the final temperature is 36.2 °C. What is the specific heat of the metal? The specific heat of water is 4.18 J/g∙°C. Report your answer to 3 significant figures.

Answer 1

use \(q=m∗C∗ΔT\), and \(q_{metal}=−q_{water}\),

so: \(\underbrace{m_*C*\Delta T}_{metal}=-(~\underbrace{m_*C*\Delta T}_{water}~)\)