Solve this system: x+2y=5 2x+4y=2
You have several different methods of solution to choose from: 1. elimination by addition or subtraction 2. elim. by substitution 3. graphing ... and several more.... Which would YOU like to try first?
Erm,I've been trying elimination uvu
So, you've been trying elimination by substitution, or elimination by addition/subtraction? Which?
addition/subtraction
OK. Let's look at our system: x+2y=5 2x+4y=2 I'd like for you to take the first equation and multiply every term in it by -2. Please type your result here.
he could just reduce the second equation
True, and I will suggest he heed your advice, later. Thanks.
my bad...I will not butt in again...sorry
-2x-4y=-20
wouldn't that be -10 instead of -20? What do you see here?
Sorry, I meant -10 but I'm trying to rush uAu
OK x+2y=5 2x+4y=2 becomes -2x-4y = -10 2x+4y=2 Please combine all the like terms. In other words, combine -2x and 2x to obtain zero. what about the y terms? what about the constants on the right side of these equations?
That was my problem, they both are eliminated! But if you plug it in, then it's as if it has no solution
And -10 doesnt equal 2
That's exactly right. Since 0 on the left side cannot equal 2-10 on the right, this system of linear equations has no solution. that's it. End of story.
Note that we're not checking whether or not -10 equals 2; instead, we're combining those quantities; result is -8, right? 0 is not equal to -8, so our system has NO SOLUTION.
Thank youso much! I thought it would be no solution but I was doubting myself. uvu
I'm so glad we could work together and that this effort confirmed your initial solution. See you again on OpenStudy!
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