solve this rational equation
x+ (10/x-2)=x^2+3x/x-2.. please!
and this one
2/x+3+5/3-x=6/x^2-9 ..

Question

solve this rational equation
x+ (10/x-2)=x^2+3x/x-2.. please!
and this one 
2/x+3+5/3-x=6/x^2-9 ..

mathmale · Answer

I'm going to try to interpret your question #1.  Is the following what you meant?$$x+ (10/x-2)=x^2+3x/x-2\rightarrow?\rightarrow x+\frac{ 10 }{ x-2}=x^2+\frac{ 3x }{x-2 }?$$Wehn you wish to indicate division of 10 by (x-2), for example, it's very important that you use those parentheses.    Otherwise, someone might interpret this as (10/x)-2.

Verify your intent; then we can proceed.

anonymous · Answer

everything is right except the x^2 is suppose to be beside the 3x

mathmale · Answer

"beside the 3x" would result in your obtaining 3x*(x-2).  I honestly don't think that that's what your posted homework problem calls for.  Could you possibly use the Equation Editor or the Draw utility for greater clarity?

anonymous · Answer

x^2+3x over x-2

mathmale · Answer

Still doesn't look appropriate to me.  Could you possibly do a screen shot and upload the screen shot to OpenStudy so that I could see the original question?

mathmale · Answer

x^2+3x over x-2  is exactly what I proposed earlier.

anonymous · Answer

ill send a picture

mathmale · Answer

$$ x+\frac{ 10 }{ x-2}=x^2+\frac{ 3x }{x-2}$$ is what I THINK you mean.