On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump if the jumper runs as at 20 miles per hour?

Question

jdoe0001 · Answer

$\bf \text{initial velocity}\

h = -\cfrac{gravity}{2}t^2+v_ot+h_o \qquad \text{in meters}
\ \quad \

v_o=\textit{initial velocity of the object}=20\
h_o=\textit{initial height of the object}=0\
h=\textit{height of the object at "t" seconds}=2\
gravity=1.67$

solve for "t" or time it took |dw:1395618244255:dw|

anonymous · Answer

thank you so much all clear now