Question

On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump if the jumper runs as at 20 miles per hour?

Answer 1

\(\bf \text{initial velocity}\\

h = -\cfrac{gravity}{2}t^2+v_ot+h_o \qquad \text{in meters}
\\ \quad \\

v_o=\textit{initial velocity of the object}=20\\
h_o=\textit{initial height of the object}=0\\
h=\textit{height of the object at "t" seconds}=2\\
gravity=1.67\)

solve for "t" or time it took

Answer 2

thank you so much all clear now