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Need help solving this inequality. (1/2p)+(3/4p)<(1/2)
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\[\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+bc}{bd}\] use this rule
I am unfamiliar with that formula which letters are which? @Jonask
\[\dfrac{1}{2p}+\dfrac{3}{4p}=\dfrac{6p}{8p}=\dfrac{3}{4}\le\dfrac{2}{4}=\dfrac{1}{2}\]
Thanks is that supposed to be 2 1/2? @Jonask
its so is it \[\dfrac{3}{4}> \dfrac{2}{4}\] since \(3> 2\) i think its supposed to be more than,not less than
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