Question

Graph 2 periods of the equation f(x) = 3cot(x + pi/2)-1

Answer 1

@thu1935 do you have any idea how to do this because I don't?

Answer 2

To graph trig trig equation, set up a Sign Table (Sign Chart) with x varies from 0 to 2Pi (2 periods = 2Pi, since the period of cot is pi).
Call f(x) = 3 cot(x + pi/2) - 1
Cal g(x) = cot (x + Pi/2). Set up a Sign Table (sign chart)
Give x consecutive values from 0 to 2Pi.. Compute g(x) by a calculator.
Compute related values of f(x).
Remember: When x = Pi/2 and x = 3Pi/2, g(x) and f(x) = - infinity and + infinity (symbol: ||). The graph would be alike to the one in the graph, but with more computed details.
Note: f(x) = 0 when cot(x + Pi/2) = 1/3 = cot A. Find A by calculator. Plot f(x) = 0 in the chart.

x |0 Pi/4 Pi/2 3Pi/4 Pi 5Pi/4 3Pi/2 7Pi/4 2Pi
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g(x)|0 - - || - - 0 - - II + + 0
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f(x)|-1 || -1 || -1