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Mathematics 8 Online
OpenStudy (anonymous):

Can someone walk me through the steps to solve this please? What is the period of the function? y = 3 cos pi x

OpenStudy (amistre64):

you first need to know what the standard period for cosine is. then we can begin to unfold how they modified it.

OpenStudy (anonymous):

is it this? y = a cos(b x)

OpenStudy (amistre64):

thats a generic representation of your stated information yes; but that is not the standard period for cosine.

OpenStudy (amistre64):

the standard period for cosine is 2pi, in other words: cos(2pi) = cos(0) pi x = 2pi, when x = 2 so the period is modified in general as: b x ...to.... 2pi/b

OpenStudy (amistre64):

now, if we have cos(1/2 x) the period is when 1/2 x = 2pi; x = 4pi 2pi --- = 4pi 1/2

OpenStudy (anonymous):

Okay so I'm a little confused now.

OpenStudy (amistre64):

how is 2pi/b confusing?

OpenStudy (anonymous):

would the period be just 2pi ?

OpenStudy (amistre64):

of course not ... since you stated the general setup at cos(b x) then the period is 2pi/b 2pi/pi = 2

OpenStudy (amistre64):

the standard unmodified period of cosine is 2pi .... cos(b x) when b=1 2pi/1 = 2pi

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