Can someone walk me through the steps to solve this please? What is the period of the function? y = 3 cos pi x
you first need to know what the standard period for cosine is. then we can begin to unfold how they modified it.
is it this? y = a cos(b x)
thats a generic representation of your stated information yes; but that is not the standard period for cosine.
the standard period for cosine is 2pi, in other words: cos(2pi) = cos(0) pi x = 2pi, when x = 2 so the period is modified in general as: b x ...to.... 2pi/b
now, if we have cos(1/2 x) the period is when 1/2 x = 2pi; x = 4pi 2pi --- = 4pi 1/2
Okay so I'm a little confused now.
how is 2pi/b confusing?
would the period be just 2pi ?
of course not ... since you stated the general setup at cos(b x) then the period is 2pi/b 2pi/pi = 2
the standard unmodified period of cosine is 2pi .... cos(b x) when b=1 2pi/1 = 2pi
Join our real-time social learning platform and learn together with your friends!