Question

Help *metals*

Answer 1

so if y varies directly as x \(\Rightarrow y = kx\)

direct variation is "directly" across the equal sign

if y varies inversely as x \(\Rightarrow y = \Large{\frac{k}{x}}\)

x is in the "inverse" position of y.

does this make sense?

Answer 2

Kinda can you still help me?

Answer 3

with?

Answer 4

this problem I'm still confused

Answer 5

okay, look at the first choice. form this you should be able to identify what type of variation and the constant, k.

can you determine these?

Answer 6

"from" not "form"

Answer 7

would it be the third answer?

Answer 8

okay, why?

Answer 9

because it's a fraction

Answer 10

no, it has to do with the position of the other variable.

Answer 11

y=7x is the answer?

Answer 12

what kind of variation is this: \(y=\Large{\frac{2}{3}}\normalsize{x}\)

Answer 13

your choice was correct but your reasoning was incorrect.

Answer 14

it is choice "C" but because the x is on the bottom, in the "inverse" position.

Answer 15

Oh I see thanks !
Can you help me with another question?

Answer 16

yes, please just do a new post so others have a chance to contribute

Answer 17

Okay

Answer 18

so what do you create?