Evaluate the following. Answers must be in EXACT VALUES!!! sin^(-1)(sin〖-135°〗 )
So start with sin〖-135°〗 BTW, fancy brackets!!
hhehe
look at your Unit Circle what's the sine of say 90 degrees?
im confused about what you are asking
i know im in the third quadrant
well.... if you look at your Unit Circle... what does it show for sine of 90 degrees?
just as an example for that matter
why are we looking at 90 degrees
its 1
There is another way: it has to do with the meaning of inverse functions. sin^(-1) and sin are inverse functions, so they cancel out. In general, if f and g are each other's inverse, this is what happens if you apply them one after the other: f(g(x))=x, so NOTHING happens! Now what do you think is the answer of your question?
so the answer is sin-135?
whatever that value is?
m terrible with trig im reliving a nightmare that i already lived in high school. but i am doing great in statistics...
hhaha
I understand your troubles! In this case, the problem is not so straightforward, because of the value -135. That is why you have to draw a unit circle. Here is one:
i get the picture
The value of sin(-135) is the same as sin(-45), as you can see in the image. Therefore, if you apply sin^-1, you don't get -135 back , but -45, because that number is closer to 0.
okay that makes sense
It is caused by the way sin^-1 is defined. It means you alway get back to angles between -90 and 90 degrees, by the same reasoning as above.
okay thank you for helping me. my daughter woke up and i have to take care of her now.
Take care of her, it is more important than maths!
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