Question

how do i work out the x intercept of 5x^2log(e)2x

Answer 1

\(\Huge\color{blue}{ \sf y=5x^2log(e)2x}\)

\(\Huge\color{blue}{ \sf 5x^2log(e)2x=0}\)

Solve for x.

Answer 2

yeah thats what i need help with

Answer 3

i forgot to say that its a function

Answer 4

something seems wrong about that notation

Answer 5

if you mean the 2x yeah it should be in brackets

Answer 6

\(\Huge\color{blueviolet}{ \sf 5x^2log(e)2x=0}\) I would combine 5x^2 and 2x first

\(\Huge\color{blueviolet}{ \sf 10x^3log(e)=0}\)

\(\Huge\color{blueviolet}{ \sf x^3log(e^{10})=0}\)

no, I am doing something wrong. Idk sorry.

Answer 7

so its
\[5x^2 \ln(2x) = 0\]

Answer 8

yeah

Answer 9

5x^2 = 0 when x = 0

ln(2x) = 0 when 2x = 1 ---> x = 1/2

Answer 10

thars correct answer