Find an equation of the line that satisfies the given conditions. Through (−1, −2);
perpendicular to the line
2x + 7y + 6 = 0

Question

Find an equation of the line that satisfies the given conditions. Through (−1, −2);
  perpendicular to the line 
2x + 7y + 6 = 0

anonymous · Answer

Do you have a graphing calculator?

blaque678 · Answer

no

anonymous · Answer

well that would make life easier lol, dude, you could graph things by hand but that would take forever... What class is this?

anonymous · Answer

yah, dude... get a graphing calculator... and like me because I am going to start a tutor youtube page and you can subscribe if you wish...

blaque678 · Answer

I don't have to graph it and I don't even know how to set it up

anonymous · Answer

Answer is 7x -2y + 3 = 0

anonymous · Answer

|dw:1395810960433:dw|

blaque678 · Answer

so really all I have to do is plug in the given numbers when its perpendicular?

anonymous · Answer

yup.. there is a condition for prpendicular lines....
ax + by + c = 0
then eqn. of perpendicul. line will be
bx - ay + d = 0

blaque678 · Answer

thanks I have to remember that

anonymous · Answer

yes and for Parallel lines..
ax + by + c = 0
it will be
ax + by + d = 0
as the slopes are always equal in case of parallel lines.. Ok .. :)