Question

help with calculus please? question attatched

Answer 1

Hint: Re-write your function as \[y=(6^{3-y)})^{\frac{ 1 }{ 2 }}.\] This is a POWER FUNCTION.

What's the Power Rule tell us?

What's the Power Rule with Chain Rule tell us?

Answer 2

so it would be 1/2 (sqrt 6^(3-y) ln6?

Answer 3

poweer function is f(x+deltax)-f(x)/deltax

Answer 4

rule*

Answer 5

oh chain rule is D(h(x))?

Answer 6

If you are given a power function such as \(y=x^2, \), the derivative of this function is \(\frac{ dy }{ dx }=2x ^{2-1}=2x,\)

Answer 7

yes

Answer 8

Yes, you must apply the chain rule as well as the power rule.

Here your outside function is y=( u )^(1/2) and your inside function is u = \[6^{3-y}.\]
Please try again to find the derivative. Apply the power rule first, then the chain rule.

Answer 9

is it negative then? -1/2(sqrt 6^(3-y))log(6)?

Answer 10

3(sqrt6^(1-y)) log(6) +1

Answer 11

maybe .. -3(sqrt6^(1-y))log(6)

Answer 12

\[ -1/2(\sqrt 6^(3-y))\log(6\]
should be\[\frac{ 1 }{ 2}(6^{3-y})^{\frac{ -1 }{ 2 }}*\frac{ d }{ dy }6^{3-y}=?\]
Please, if at all possible, use the Equation Editor for greater clarity. Thanks.

Answer 13

oh ok so its \[(-\ln(6)(6^(3/2)-(y/2)))/2\]

Answer 14

the (3/2-y/2) is all ^..

Answer 15

@skullofreak: Please demonstrate how you would obtain the derivative of

\[6^{3-y}.\]

Answer 16

If you're unfamiliar with equation Editor, please use the Draw feature instead. Show each step, please.