Solve for h. a = ch + f
@AccessDenied
So we start from here: \( a = c\color{lime}{h} + f \) Highlighting the variable. We generally work with reverse order of operations to solve. The first step is to move the items added or subtracted to the other side of the equation until the term with h is alone.
|dw:1395866694210:dw|
So right now, we have f added to ch. That needs to be moved first. The operation that cancels adding f is subtracting f, and we do so on both sides: \( a \color{red}{- f}= c\color{lime}{h} + f \color{red}{- f} \) Notice the right-hand side, we add and subtract f. This leads to a net addition of 0. :) \( a - f = c \color{lime}h \)
b
Yup, so we would then divide both sides by c to cancel the c attached to h by multiplication: \( \dfrac{a - f}{\color{red}c} = \dfrac{c\color{lime}{h}}{\color{red}c} \) \( \dfrac{a - f}{c} = \color{lime}h \)
thanks!
No problem! :)
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