Factor the following problem completely. First, factor out the greatest common factor, and then factor the remaining trinomial: 2y^4 − 4y^3 − 30y^2
GCF = 2y^2
2y^2(y^2 - 2y - 15) now you need to factor the trinomial in the parentheses
I have no idea what to do next...
ok tghis will factor to the form (x + a)(x + b) where ab = the last term ( -15 ) and a + b = -2 ( the coefficient of 2) ab = -15 one possibility = -5 and +3 what is the value of a + b ?
2y^2(y^2 - 2y - 15)
a + b = -5 + 3 = -2 so that it factors are 2y^2(y - 5)(y + 3)
oooooh ok, thank you !
yw to get the factors you do this -5 and + 3 give us the 2 middle terms -5y + 3y y^2 - 2y - 15 = y^2 -5y + 3y - 15 grouping in pairs: = y(y - 5) + 3 (y - 5) = (y + 3)(y - 5)
So, if you add it together, it equals the middle term, but when you multiply it, it equals the last term?
right
eg x^2 - 5x + 6 what do you think the 2 numbers would be in this case ?
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