Find the area of the region in the first quadrant (upper right quadrant) bounded by the curves y = sin x cos2x, y = 2x cox(x2), and y = 4 – 4x.

Question

anonymous · Answer

@mathmale hi! lol

anonymous · Answer

i just need help solving the b-a part

anonymous · Answer

i dont know which curves to use to find the boundaries

mathmale · Answer

"LOL" is right.  This is a very challenging problem.  
I do see that x begins with 0 and that y also begins with 0 (due to the phrase "first quadrant."

mathmale · Answer

Secondly, I need to verify that I understand your presentation of these functions.  Are the following correct or not?

anonymous · Answer

yes.

mathmale · Answer

$$ y = \sin x *\cos2x, y = 2*x *\cos(x^2)$$

anonymous · Answer

i got it! lower bound=0 upper bound is pi/4.

mathmale · Answer

I'm curious how you arrived at that upper bound.  Was it given?  I haven't actually done this problem, so don't know yet what my own answer would look like.