Question

Graph the polar curve.. r^2 = sin2(o).. how do I simplify this?

Answer 1

Is that \(\sin^{2}(\theta)\;or\;\sin(2\theta)\;or\;something\;else?\)

Answer 2

\[r^2=\sin2 \theta \]

Answer 3

What's stopping you from picking various values of \(\theta\)?

Answer 4

The \[r^2\]

Answer 5

\(\theta = 0 \implies \sin(2\theta) = \sin(2(0)) = \sin(0) = 0\implies r = 0\)

Okay, no you do \(\theta = \pi/12\).

Answer 6

theta = pi/12

sin(2*pi/12)= 1/2

do I square root 1/2 or..?

Answer 7

Why would you do anything else? \(r^{2} = 1/2 \implies r = 1/\sqrt{2}\;or\;r = -1/\sqrt{2}\)

Let's roll on. Try \(\theta = \pi/8\).