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sup
\[\frac{ 1 }{ 2 }x^2+1=0\]
@tylorherpeche do you know how to solve it?
i might
subtract 1 from each side.
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\[1/2x^2=-1\]
dang it u know i swear i was just about to say that
no joke
so what about the fraction
try to isolate \[x^2\]
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and the fraction?
do I divide both sides by 0.5?
multiply each side by 2
to isolate \[x^2\] on the left side.. so now you have \[x^2=-2\]
oh Never Mind
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so then is the square root right?
|dw:1395932048992:dw|
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