Question

i need help with these questions on 11-7 section.I will attach it.

Answer 1

help

Answer 2

help

Answer 3

Please choose any two problems and say what kind of help you need. I'd prefer not to see so many questions posted at once.

Answer 4

11-7

Answer 5

only 7 questions

Answer 6

i can't paste it

Answer 7

angles of elevation and depresssion

Answer 8

Define "angle of depression" as best you can, please.

Answer 9

just read it

Answer 10

can you just tell me if i should use cosine,sine,or tangent for each question and the equation for each

Answer 11

There's no point in talking about finding or using an "angle of depression" unless you know what this term means, is there?

Answer 12

Describe what we are asked to do in the first problem for Section 11-7.

Answer 13

Once I know you can describe what you're looking for, I'd be happy to help with the trigonometry involved.

Answer 14

just tell me what i asked because i am confused about that

Answer 15

which one to use for each and the equation for each

Answer 16

I'll explain what you're looking for, to help you get started, but you'll need to explain your goal for each future problem.

In 11-7-1, you're looking for the horizontal distance that the plane flies. The plane neither gains nor loses altitude; it flies in a straight line.

Answer 17

Is the plane's horizontal path the "adjacent side" or the "opposite side" of the 3-degree angle?

Answer 18

so do we use sine,right?

Answer 19

opposite

Answer 20

Would you please answer my question. I'm trying to help you to understand the terminology used here, so that future problems will be easier for you.

Answer 21

The plane flies a straight, horiz. path. Is this path the adjacent side or the opposite side of the 3-degree angle?

Answer 22

oh adjacent

Answer 23

Right, thank you.
Now which function (tangent, cosine or sine) connects the 3-degree angle, the opposite side and the adjacent side?

Answer 24

tangent

Answer 25

Right. You're doing fine.
Now, what is the length of the opposite side?
How would you represent the length of the adjacent side?

Answer 26

0.75 is the opposite and the adjacent is x

Answer 27

Great.

Answer 28

\[\tan \theta = opp/adj = \frac{ ? }{ ? }\]

Answer 29

so is it tan 3 degrees=.75/x
0.0524=.75/x

Answer 30

Very nice. Please solve for x.

Answer 31

i will do it now,please wait

Answer 32

x=.0393

Answer 33

Would you please show me how you got that? The plane is .75 mile above the ground, but only flies 0.0393 miles horizontally? Does that make sense?

Answer 34

oh i was suppose to divide

Answer 35

please wait

Answer 36

to the nearest tenth:x=14.3 miles

Answer 37

Good. Hope you learned something of value from our discussion.

If you like, pick one more problem to work on. Not #2.

Answer 38

i know what is two
Tan 55 degrees=x/60

Answer 39

#2 doesn't show what x represents. I think you should move on to some other problem.

Answer 40

# 3 is Sine 40 degrees=x/90

Answer 41

If you let x be the vertical depth, then your equation is OK.

Answer 42

which ?

Answer 43

# 3 is Sine 40 degrees=x/90 is good.
Regarding #2: Since x is not marked on the diagram, we'll either skip this problem or assume that is the depth of the canyon.
One more?

Answer 44

#4 is Tan 50 degrees=x/75

Answer 45

can u help me with 5,6,and 7 if 4 is correct

Answer 46

just 3 more problems,please!!

Answer 47

I have to disagree with #4: #4 is Tan 50 degrees=x/75. No. x is the total height of the building, but the eyes of the observer are 4 feet above the ground.

Answer 48

Where are you located at the present?

Answer 49

then you add 4 ft to it to get x

Answer 50

i forgot to mention that

Answer 51

Sounds good.

Answer 52

an u help with 5,6 ,and 7,only those three

Answer 53

Are you in the USA, or ... ?
Pick one of those 3 problems.

Answer 54

5

Answer 55

All right. What kind of help do you need with #5?