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Mathematics 16 Online
OpenStudy (anonymous):

7√6/32

OpenStudy (anonymous):

OpenStudy (anonymous):

@love10129151 Can you help?

OpenStudy (anonymous):

@doc

OpenStudy (love10129151):

umm let me try

OpenStudy (anonymous):

Ok please!

OpenStudy (love10129151):

is it multi choice

OpenStudy (anonymous):

No

OpenStudy (anonymous):

@doc.brown

OpenStudy (anonymous):

7 * sqrt(6/32) sqrt(6/32) = sqrt(3)/4 7sqrt(3) / 4

OpenStudy (anonymous):

Why would you make it equal to √3/4?

OpenStudy (anonymous):

It's simplified because the entire fraction is not under a radical

OpenStudy (anonymous):

But the square root of 6 isn't 3

OpenStudy (anonymous):

Can you draw it ut for me?

OpenStudy (anonymous):

It's asking 7* sqrt(6/32). The sqaure root of (6/32) is the same as sqrt(3)/4

OpenStudy (anonymous):

Oh! Wait so you divide 6 by 2 and 32 by 8? But isnt it where you have to divide the numerator and denomonator by the same #?

OpenStudy (anonymous):

(6/32) = (3/16) sqrt(3/16) = sqrt(3)/sqrt(16) =sqrt(3)/4 7( sqrt(3)/4) = 7sqrt(3)/4

OpenStudy (anonymous):

Does that make more sense?

OpenStudy (anonymous):

(6/32) = (3/16) because (3/16) is a reduced fraction of (6/32). I divided both numbers by 2

OpenStudy (anonymous):

Oh! Yes thank you so much!

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