finding the slope of the tangent with e^9 in it??
i got 8e^9..but how would i write that in exact decimal form?
you don't have to
i put 8e^(9)x , and also e^(9)x.. but it says its wrong! :(
Hmm I came up with something very different for the slope at e^9..
You're doing implicit differentiation?
i just found the derivative andpluged in (1, e^9) for x and y
first, just get the general tangent formula for the equation you were given. it's implicitly done then evaluate it at the point you were given
Did you remember to apply the `product rule` to the middle term?
Yes, that's a good approach skull, let's make sure your derivative is correct though :)
i got ((9x-1)y)/x for the derivative
\[(9x-1)y/1\]
can you show us all the steps?
ln(xy) = 9x e^[ln(xy)] = e^(9x) xy = e^(9x) y = [e^(9x)] / x y' = [e^(9x) * (9x - 1)] / (x^2) y'(x = 1) = [e^(9*1) * (9*1 - 1)] / (1^2) = 8*e^9
@nincompoop
nvm it was asking for the equation! :)
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