Question

How can I find the factors of (2x^2-9x-5). Please show steps.

Answer 1

Try the "AC" method.
That is, in ax^2 + bx + c,
multiply a*c
split b into two parts so that it adds up to b and the product is ac.

Here you have 2x^2 - 9x - 5
2 * (-5) = -10

Split the middle -9 so that the sum is -9 and the product is -10
-9 = -10 + 1. The sum is -9 and the product is -10

So 2x^2 - 9x - 5 = 2x^2 -10x + 1x - 5
Factor the first two terms and the last two terms:
2x(x - 5) + 1(x - 5)
(x-5)(2x+1)

Answer 2

I see, that makes sense. Thank you again ranga!

Answer 3

You are welcome.