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OpenStudy (anonymous):

Simplify: (6x2 - 3 + 5x3) - (4x3 - 2x2 - 16)

OpenStudy (anonymous):

I'm going to assume that the numbers after the x are exponents. Correct?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Do you know how to distribute the minus sign in the middle?

OpenStudy (anonymous):

Start by reordering the first polynomial starting with the highest order term

OpenStudy (anonymous):

Then multiply -1 by each terms inside the parentheses

OpenStudy (anonymous):

x3 + 8x2 + 13 is what i am getting.

OpenStudy (anonymous):

Yeah correct

OpenStudy (anonymous):

I combined like terms and then arranged the completed terms by highest order, is that correct

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

You should get -5x3+6x2-3-4x3-2x2-16) Then you subtract 4x3 from -5x3 to get -9x3 So -9x3+6x3-3+2x2+16 Add 6x2 and 2x2 to get 8x2 Now the problem looks like -9x3+8x2-3+16 There's one more step after this. Do you know what it is?

OpenStudy (anonymous):

Where did the negative 5x^3 come from? You're only supposed to distribute the negative sign to the expression on the right side. BasedGod1122 was correct.

OpenStudy (anonymous):

I've got another one for you. Choose the correct simplification of the expression (8x - 5)(2x2 - 5x - 6).

OpenStudy (anonymous):

You just distribute.

OpenStudy (anonymous):

Multiply 8x to 2x^2, -5x, and -6

OpenStudy (anonymous):

That's the first part and you do the same thing with -5

OpenStudy (anonymous):

@BasedGod1122 do you have answer choices for your first question because I'm sure the answer is -9x^3+8x^2+13

OpenStudy (anonymous):

(6x2 - 3 + 5x3) - (4x3 - 2x2 - 16) First step: Distribute the negative sign. 6x^2 - 3 +5x^3 - 4x^3 +2x^2 + 16 And then you combine like terms

OpenStudy (anonymous):

Arranging the terms is unnecessary until the end

OpenStudy (anonymous):

What is your final answer @turquoisee?

OpenStudy (anonymous):

It was what BasedGod1122 got

OpenStudy (anonymous):

x^3 + 8x^2 + 13

OpenStudy (anonymous):

I don't think that's the correct answer but if @basedgod1122 thinks it is then he should go with that

OpenStudy (anonymous):

The answer I got was an answer choice, and one of the only remotely plausible ones.

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

Did you get the second question?

OpenStudy (anonymous):

Yes I did, thanks turquoisee

OpenStudy (anonymous):

No problem!

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