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(x+2i) (y-i)=-4-7i
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what do you get when you expand the left hand side of that equation?
xy-xi+2yi-2 OR (xy-2)+(-x+2y)i
very good, now just compare the real parts and imaginary parts on each side
xy-2=-4 AND -x+2y=-7i
Sorry xy-2=-4 AND -x+2y=-7
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That's right
so you now have a system of two equations
Yes, but here is my blackout
solve this second equation -x+2y=-7 for x, then sub that into the first equation you should get a quadratic for y
Thanks that is why I have two pairs of answers
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yep, unfortunately these final answers aren't pretty
See you
whoops i missed something, in the first step, the expansion 2i times -i should be -2i^2 = -2(-1) = 2, [not -2] sorry
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