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Mathematics 19 Online
OpenStudy (anonymous):

(x+2i) (y-i)=-4-7i

OpenStudy (unklerhaukus):

what do you get when you expand the left hand side of that equation?

OpenStudy (anonymous):

xy-xi+2yi-2 OR (xy-2)+(-x+2y)i

OpenStudy (unklerhaukus):

very good, now just compare the real parts and imaginary parts on each side

OpenStudy (anonymous):

xy-2=-4 AND -x+2y=-7i

OpenStudy (anonymous):

Sorry xy-2=-4 AND -x+2y=-7

OpenStudy (unklerhaukus):

That's right

OpenStudy (unklerhaukus):

so you now have a system of two equations

OpenStudy (anonymous):

Yes, but here is my blackout

OpenStudy (unklerhaukus):

solve this second equation -x+2y=-7 for x, then sub that into the first equation you should get a quadratic for y

OpenStudy (anonymous):

Thanks that is why I have two pairs of answers

OpenStudy (unklerhaukus):

yep, unfortunately these final answers aren't pretty

OpenStudy (anonymous):

See you

OpenStudy (unklerhaukus):

whoops i missed something, in the first step, the expansion 2i times -i should be -2i^2 = -2(-1) = 2, [not -2] sorry

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