Question

Write the expression in standard form.
five divided by quantity three minus fifteen i.

Answer 1

(5/78)-(25/78)i
(5/78)+(25/78)i
-(5/78)+(25/78)i
-(5/78)-(25/78)i

Answer 2

it has to be one of those .-. @surjithayer

Answer 3

\[\frac{ 5 }{ 3-15\iota }\times \frac{ 3+15\iota }{ 3+15\iota }\]
simplify it.
\[use~ (a+b \iota )(a-b \iota )=a^2-\iota^2b^2=a^2+b^2\]

Answer 4

where do you find the beginning of that equation?

Answer 5

previously i have not seen i after fifteen

Answer 6

okay, but i don't understand where to put everything in that equation

Answer 7

i have rationalise the denominator.

Answer 8

multiply the numerator,denominator i have shown above to solve it.

Answer 9

sorry my computer shut down .-. okay so to do that would you foil the denominators and numerators with eachother?

Answer 10

\[=\frac{ 5\left( 3+15\iota \right) }{ \left( 3 \right)^2-\left( 15\iota \right)^2 }\]
\[=\frac{ 15+75\iota }{9-225i^2 }\]
\[\iota^2=-1\]
now you can solve.

Answer 11

(15+75i)/134
15/134 +75i/134
but how do you simplify 134 into 78?
@surjithayer

Answer 12

it is 234 not 134
cancel the numerator and denominator by 3

Answer 13

9+225=234

Answer 14

3/78 + 25i/78 so they would both be positive?

Answer 15

5/78 not 3/78

Answer 16

oh okay thank you ^.^

Answer 17

yw