What is the equation of a circle with center at (-7,-6) and radius of 2??

Question

anonymous · Answer

the form of a circle:
(a-x)^2+(b-y)^2 = r^2
(x, y) = (-7, -6)
r = radius

anonymous · Answer

plug your variables in.

anonymous · Answer

er, well technically it should be
(x-a)2+(y-b)^2 = r^2
(a, b) = (-7, -6)
r = radius)

jdoe0001 · Answer

http://www.mathwarehouse.com/geometry/circle/images/equation-of-circle/example-2-equation-of-circle.png

anonymous · Answer

(x+7)^2+(x+6)^2=4

agent0smith · Answer

@bloopman your first formula is equivalent to the second hehe. If you factor out a negative from each of the brackets in:
$$\Large (a-x)^2+(b-y)^2 = r^2$$you get
$$\Large (x-a)^2+(y-b)^2 = r^2$$

anonymous · Answer

@agent0smith i know they're equivalent :P
but when you substitute in x and y in as the coordinates, you get an equation in terms of a and b, which isn't conventional.

agent0smith · Answer

Yeah, it looks weird.

agent0smith · Answer

Oh i see, you listed the center as (x, y) = (-7, -6)