factor 4x^2 - 4x + 1 = 0
I know the outcome would be (2x-1)=0, but what is the method?
What do you mean by method??
How exactly do you get it, how do you factor it.
I completely forgot how to factor these types of problems.
Complete the square
Ah, alright. Do you think you can show me how to do it again?
This website might be a little helpful! http://www.mathsisfun.com/algebra/completing-square.html
You need factors of 4*1 = 4 that sum to -4. What are they? and I'll help you with the next step.
Well that would be just -2.
Right, -2 * -2 = 4. since the factors are the same, you know you have a perfect square trinomial, which factors into the same factor, twice.
Thefactors of 4x^2 are 2x and 2x; the factors of +1 are -1 and -1, so the trinomial factors into (2x-1)(2x-1) or (2x-1)^2
Each factor produces the same root (solution) when set equal to zero, so you just have to solve 2x - 1 = 0 by adding 1 and dividing by 2.
Perfect Square Factoring Formulas a² - 2ab + b² = (a - b)² a² + 2ab + b² = (a + b)²
Ah alright. That makes more sense. I got confused for a second.
In your case, a is 2x, and b is 1 in the top formula
Alright thanks man.
ur welcome
Join our real-time social learning platform and learn together with your friends!