Graph y=4x-1 using the SLOPE AND Y-INTERCEPT METHOD. m=?? b=??
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y=mx+b is the standard for of slope intercept m replaces 4 and b relaces -1 y=4x+(-1) y=4x-1 y-intercept or b is (0,-1) and the line, the steepness of it has a slope of 4
humm but it says she should use slope intersect to drow
m= tan theta so theta = tan^-1 4
theta =47.96... and point of intrsect is (0,-1)
so plot (0,-1) |dw:1396213133997:dw|
alrighty so m=4 and b=-1
then plot theta ! theta =75.96
do i need to draw a line through that point ?
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yess , see m=4 m= slope = tangent =\( \tan\theta\)
im a bit confused about the formula you're using because i'm in grade 9 and we never learned about tan
like we never used it like..ever
ohh ok do u know sin , cos ??
nope none of those
ohh humm then why it asked for SLOPE AND Y-INTERCEPT METHOD. humm then use @Zale101 idea ^_^
i think there is a different way to solve it with the slope and y-int method
without the sin and cos and tan thing ...because i don't know about those
yess there is :D
so yea zale probably knows...
try plotting points, it's an easier method to use :)
only find onother point on the line y=0 x= 1/4
you're finding the line of the equation, right?
i have no idea, like the question on the paper literally matches the question i typed out here
and i'm not the best at this linear relations unit so i don't know where to start
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