Question

solved

Answer 1

what are you supposed to do with it?

Answer 2

Solving for X

e is 2.78[...] or the inverse of Ln

Answer 3

I can only get one side of it before I get lost and can't compete the other side.

Answer 4

multiply out, combine like terms etc

Answer 5

\[e^x+e^{-x}=2e^x-2e^{-x}\]
\[e^x-3e^{-x}=0\] and since \(e^x\) is never zero, you can multiply by \(e^x\) to get
\[e^{2x}-3=0\]

Answer 6

you good from there?

Answer 7

So then I would go 2x=Ln[3] then divide by 2 to get x?

Answer 8

yup

Answer 9

Awesome thank you very much!

Answer 10

yw