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x^2-7x+4/x+3
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give the equation of the oblique asymptote
please help
when x approaches 0 what happens to the value of 4/x?
what do you mean? dont you have to use synthetic division?
I'm pointing out that x=0 is where y goes to negative and positive infinity
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notice that if you take out the 4/x the graph looks similar, save no spiking to negative and positive infinity.
when i tried calculating it out i got x-10 as the oblique is that correct?
divide, you will get a quotient and a remainder ignore the remainder, the quotient is your oblique asympote
yes, \(y=x-10\) is right
thank you :)
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yw you did all the work!
youll notice that y=x-10 intersects with the graph, and therefore can't be an asymptote.
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