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Factor the following expression. Show the steps to the final answer.
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\[198q^3r^2-184q^2r^2+18qr^2\]
first look at the numbers and find their greatest common factor (GCF)
they are all even so 2 is a possibility write them as prime factors 18 = 2*3*3
will 6 or 9 divide exactly into 184?
hang on....
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no
ok so the GCF of the numbers is 2 the GCF of the variables is easy eg q^3, q^2 and q the greatest factor which divides into these 3 is q the terms in r are all r^2 so GCF of these is r^2 so your GCF is 2qr^2 take this out and divide each term by 2qr^2 to getthe other factor in the parentheses
I'm lost....i have no clue...
Never mind i got it. Thanks for your help!:)
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