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integral help! (cal 2) posted below! thanks in advance!
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\[\int\limits_{}^{} \frac{ 3\sec ^{2}t }{ 6+3\tan t }dt\]
put tan t=x sec^2 t dt=dx
I think my first step should be a substitution. so im thinking the bottom somehow
ahh ok let me start with this
first take common 3 from numerator and denominator and cancel ,then substitute as above.
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\[\int\limits_{}^{}\frac{ dx }{ 2+x }\]
correct now integrate.
i take another substitution?
no need when numerator is diff. of denominator \[\int\limits \frac{ f'(x) }{ f(x) }dx=\ln \left| f(x) \right|\]
sorry, i am just learning this and these are some of the class examples i have written down
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ooooh! makes sense because the derivative of lnx is 1/x
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