Question

Help please:
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Answer 1

Any equation with this form will need to be squared twice \(x,y,b\ne0\)
$$
\sqrt{x}=\sqrt y + b
$$

does this make sense?

Answer 2

Do you see the pattern?

Answer 3

For example -

Answer 4

Does this make sense?

Answer 5

The equation type, like example 1, needs to square twice both sides in order to solve it.
Vy + 1 = V(y + 5)
Square first time: (Vy + 1)^2 = V(y + 5)^2
y + 2Vy + 1 = 5 + 2 -> 2Vy = (-y + 6)
Square the second time:
4y = (6 - y)^2 = y^2 - 12y + 36 -> y^2 - 16y + 36 = 0
This quadratic equation can now be solved to get y.
The answers are: 1, 2, 5, 9, 11, and 15.