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Mathematics 14 Online
OpenStudy (anonymous):

I really need help with my Algebra 2 polynomial equation work. Someone please help me im begging!

OpenStudy (anonymous):

First, here is the existing map of current structures. It is important that the rollercoaster does not go through the foundation of any of these structures. 1st point: ___6___ 2nd point:___-2___ 3rd point: ___-7___ Using the points above as zeros, construct the polynomial function, f(x), that will be the path of your rollercoaster. Show all of your work. Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your funtion matches your graph. Use complete sentences. Solve for the y–intercept for your function, f(x), and then construct a rough graph of your rollercoaster. If your y–intercept is off the graph, give the coordinates of the y–intercept.

OpenStudy (anonymous):

thats everything someone please guide me through it and teach it to me i would love that

OpenStudy (mathmale):

1st point: ___6___ 2nd point:___-2___ 3rd point: ___-7___ Using the points above as zeros, construct the polynomial function, f(x), that will be the path of your rollercoaster. Show all of your work. First, think of "the foundation" as being the x-axis. In other wordsd, the roller coaster touches the x- axis at -7, at -2 and at 6, but does not go beneath the x-axis. Thus, you automatically have three on the curve formed by the roller coaster. Are you aware that a root of 6 corresponds to the factor (6,0) of the polynomial in question? What are the other two factors, following this pattern? You can obtain the polynomial in question by multiplying out the three factors mentioned. Try this, and then get back here to request some feedback. Good luck!!

OpenStudy (anonymous):

what? i am so confused @mathmale

OpenStudy (anonymous):

so if i have (6,0) and (-2,0) and (-7,0) what do i do

OpenStudy (anonymous):

@mathmale how do i make a polynomial function with those

OpenStudy (mathmale):

(6,0) and (-2,0) and (-7,0) are points on the x-axis; they're not factors. what I was trying to tell you was that if one root is 6, one factor is (x-6); if another root is -2, the corresponding factor is (x-[-2]). What is the third factor? To get started finding your polynomial, please multiply together (x-6) and (x+2).

OpenStudy (anonymous):

the third factor is (x-(-7) @mathmale

OpenStudy (anonymous):

and ill get x^2-4x-12 @mathmale

OpenStudy (mathmale):

Right. So, now you have three horiz. intercepts, (6,0) and (-2,0) and (-7,0) , and you have three factors, (x-6),(x+2) and (x+7). Now, with x^2-4x-12 in hand, multiply this polynomial by the third factor, (x+7). Combine like terms. Write your function so that all powers of x are in descending order. Then you'll have your polynomial.

OpenStudy (anonymous):

x^3+x^2-28x-12x-84 @mathmale

OpenStudy (anonymous):

@mathmale What do i do now? the next step i REALLY dont get at all

OpenStudy (mathmale):

Your function / your polynomial is f(x)=x^3 + x^2 -28x -12x - 84 . Nice work!

OpenStudy (anonymous):

@mathmale but what about the next part

OpenStudy (davidusa):

MATHMALE IS GOOD. GIVE HIM A MEDAL. :D

OpenStudy (anonymous):

@DavidUsa I was planning on it when we were done

OpenStudy (davidusa):

yay :):D

OpenStudy (mathmale):

Second part: " Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your funtion matches your graph. Use complete sentences." I have to admit that I don't remember the details of either the Theorem or Descartes' Rule of Signs. However, thanks to the Internet, it'd be a simple matter to look them up. I'd suggest you start by Googling Descartes' Rule of Signs; by doing that you'd have an excellent chance of finding an explanation with examples of this rule. the whole idea is to determine whether or not the graph crosses the x-axis or not. In our case, here, we'd hope that the Rule of Signs would predict that the graph does not cross the x-axis. But don't take my word for it; please research this in your textbook or through a Google search.

OpenStudy (anonymous):

can i use an actual graphing program to see if it does @mathmale

OpenStudy (mathmale):

Certainly! that won't satisfy the requirement that you use both of the two methods named to arrive at your answer, but the more you know about the shape of the graph, and whether or not it touches / crosses the x-axis, the better!

OpenStudy (anonymous):

@mathmale can you help me with question 3

OpenStudy (davidusa):

ummm.... just saying.... u dont have to write @mathmale. @davidusa. @blah. everytime

OpenStudy (mathmale):

Princess: I used wolframalpha.com to graph your function: http://www.wolframalpha.com/input/?i=f%28x%29%3Dx%5E3+%2B+x%5E2+-28x+-12x+-+84 Unfortunately, wolframalpha shows that the graph of your function DOES cross the x-axis. This means we'll need to go back and double-check the multiplication of those three factors.

OpenStudy (anonymous):

so what do we do if it's all right?

OpenStudy (anonymous):

like what do we need to change

OpenStudy (anonymous):

@mathmale

OpenStudy (mathmale):

Hold a moment, please. Don't worry, I'm sticking with you and this conversation. One thing you could do would be to copy down your 3 factors and multiply them together again, in different order, and then compare the result to your original f(x).

OpenStudy (anonymous):

ok one second im doing it now

OpenStudy (mathmale):

Aha. Reading the problem statement again, I see mention of "a map of current structures." Was there an illustration with this problem? If so, would you please post it?

OpenStudy (anonymous):

the map is the picture i posted

OpenStudy (mathmale):

If these structures have their floors / foundations at different levels, then it's entirely possible that our polynomial is just fine, and that the graph DOES cross the x-axis.

OpenStudy (anonymous):

As one of the new rollercoaster engineers, you have been tasked with developing a rollercoaster that will intertwine with existing Oakville Lake Amusement Park structures. For one of the more thrilling sections, the rollercoaster will dive down in-between buildings, plummet underground, pop back up, and coast over a hill before shooting back underground. There must be three distinct points where the rollercoaster crosses the x–axis. Precise measurements and attention to detail are very important.

OpenStudy (anonymous):

this is at the very begging

OpenStudy (mathmale):

Aw, shoot. Your illustration shows that all of the structures have their foundations at the same level, so that means my hypothesis is shot. " plummet underground, pop back up, and coast over a hill before shooting back underground" uh-oh. So the path of the roller coaster DOES cross the x-axis. Proof, beloved proof! So let's go back and take a look at the graph we got courtesy of wolframalpha.com.

OpenStudy (anonymous):

so does that mean the polynomial is fine or do i need another one

OpenStudy (anonymous):

because i have another one if you need one

OpenStudy (davidusa):

mousy

OpenStudy (anonymous):

@mathslover What does the graph mean

OpenStudy (anonymous):

omg does it go around the figures

OpenStudy (mathmale):

Look at the first part of your problem statement: "As one of the new rollercoaster engineers, you have been tasked with developing a rollercoaster that will intertwine with existing Oakville Lake Amusement Park structures. For one of the more thrilling sections, the rollercoaster will dive down in-between buildings, plummet underground, pop back up, and coast over a hill before shooting back underground. There must be three distinct points where the rollercoaster crosses the x–axis. Precise measurements and attention to detail are very important." Then look at the graph (courtesy of wolframalpha.com): At how many places does this graph cross the x-axis?

OpenStudy (anonymous):

the graph does that!

OpenStudy (mathmale):

Yes, it crosses the x-axis in 3 places. So, it appears that we're right on target.

OpenStudy (anonymous):

so is that it?

OpenStudy (mathmale):

No. Read the last part of the problem statement and type, in your own words, what we still have left to do.

OpenStudy (anonymous):

how do i solve for the y inercept

OpenStudy (anonymous):

oh ok :)

OpenStudy (mathmale):

Suppose I gave you f(x)=x^2 -x -3. How would you find the y-intercept of the graph of this function?

OpenStudy (anonymous):

plug in numbers for x

OpenStudy (mathmale):

What number(s) would you plug in?

OpenStudy (anonymous):

i have no idea ahaha

OpenStudy (mathmale):

What does "y-intercept" mean to you?

OpenStudy (mathmale):

Important concept, especially in graphing.

OpenStudy (anonymous):

the vertical up and down line

OpenStudy (mathmale):

that's the y-axis. Our task is to determine where the graph crosses the y-axis. Plese look at the graph again: http://www.wolframalpha.com/input/?i=f%28x%29%3D%28x-6%29%28x%2B2%29%28x%2B7%29 Estimate the y-value where the graph crosses the y-axis.

OpenStudy (anonymous):

it crosses the y axis at 0,0

OpenStudy (anonymous):

oh wait wrong graph

OpenStudy (mathmale):

(0,0) is the origin; I see that the graph crosses the y-axis below the origin (so that the y-value in question is negative).

OpenStudy (anonymous):

so did we find the y

OpenStudy (mathmale):

Not yet. Have you looked at the graph by wolframalpha.com? http://www.wolframalpha.com/input/?i=f%28x%29%3D%28x-6%29%28x%2B2%29%28x%2B7%29 Look at it again, and then estimate the y-value where the curve crosses the y-axis.

OpenStudy (anonymous):

which graph am i supposed to look at the first of second one

OpenStudy (anonymous):

is it (-5,0)

OpenStudy (mathmale):

the first scale division is -200, right? So, does it sound right when I suggest that the curve crosses the y-axis at about -80?

OpenStudy (mathmale):

When writing the y-intercept, Princess, you'd want to write it as (0, Y) (0 first, Y second).

OpenStudy (anonymous):

oh! omg i was looking at the x axis for some reason

OpenStudy (anonymous):

so its (0,-80)

OpenStudy (mathmale):

Approx. Just a sec, please.

OpenStudy (anonymous):

ok

OpenStudy (mathmale):

the function you came up with is f(x)=x^3 + x^2 -28x -12x - 84. Would you now please let x=0 and calculate y=f(0).

OpenStudy (anonymous):

so everywhere that there is an x i put 0

OpenStudy (mathmale):

Right on.

OpenStudy (anonymous):

f(x)=84

OpenStudy (mathmale):

Actually, it'd be f(0) = -84, wouldn't it?

OpenStudy (anonymous):

yes!

OpenStudy (mathmale):

So, by letting x=0, you have arrived at f(0)=-84; this point can be written as (0,-84). By what name shall we call this point? (I'm always trying to review stuff!).

OpenStudy (anonymous):

the y intercept?

OpenStudy (mathmale):

Right! And although you still have to respond to the request for verbal explanations in this problem statement, you're essentially done with the number-crunching (math) part. :)

OpenStudy (anonymous):

so i would basically say that i put 0's in for all of the x's and then do the math

OpenStudy (mathmale):

True ... but I'm afraid you'll also have to explain other parts of the problem solution as well. Don't want to ruin your evening! But that's what the problem asks for.

OpenStudy (anonymous):

youre not ruining my evening haha but do you mean that i explain the rest of what i did

OpenStudy (mathmale):

From the original problem statement: "Using both fundamental Theorem and Descartes` rule of signs, prove to the construction foreman that your funtion matches your graph. Use complete sentences."

OpenStudy (anonymous):

oooooh ok

OpenStudy (anonymous):

i looked those up and i still dont understand them

OpenStudy (mathmale):

Best to you, Princess. Do call on me again in the future. Good night!

OpenStudy (anonymous):

ok and thank you for everything :)

OpenStudy (mathmale):

I won't be able to go into those right now, but perhaps if you could catch me online tomorrow, we could look them up together and discuss them. Have you a textbook for this course, a real, paper textbook?

OpenStudy (anonymous):

nope becuase i am doing virtual school

OpenStudy (davidusa):

MATHMALE IS HELPFUL HE DESERVES A FAN FOR HIS HARD WORK :D

OpenStudy (anonymous):

david im not trying to be mean but why are you still here?

OpenStudy (davidusa):

im talking to mathmale and watching him do magic

OpenStudy (mathmale):

I meant: Your being a virtual school student ... that poses a REAL challenge. As I'm deaf, it's hard for me to conceive of learning math without textbooks. As an online student you have to develop skills not only in learning stuff but also in finding it first online. I hope we can meet tomorrow to discuss this further.

OpenStudy (anonymous):

i love being an online student :) I have straight A's

OpenStudy (anonymous):

omg your deaf ive never met a deaf person!

OpenStudy (mathmale):

that's fantastic, Princess!!

OpenStudy (anonymous):

youre so cool!

OpenStudy (mathmale):

I do get a kick out of helping others online, not intentionallyl concealing the fact that I'm deaf, but realizing that my being deaf does not in any way lessen my ability to help with Math.

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