Question

90. A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure was 1.00 atm, what would the final pressure be?

Answer 1

If the moles of the K is the same here is the equation.

Laws of Gas Law:

(v1*p1)/(n1*T1)=(v2*p2)/ (n2*T2)

V equals pressure

p equals pressure

n equals moles

T= temperature in Kelvin

V1=24L
V2=35
P1=1 atm
P2=?
T1=263.0 K
T2=298 K
n1=it would not matter because the amount of K would be the same.
N2= It does not matter when you divide the same moles of K between n1 and n2 will be 1, so it is irrelevant for now.

Renew equation to find Final P2

P2= (n2*T2*V1*P1)/ (V2*n1*T1)

(1*298*24*1)/(35*1*263)=.7769 atm

If you use qauntivive reasoning pressure decreases as you increase volume. Final Pressure= .7769atm

Answer 2

thank u so much

Answer 3

No problem :)