factorizen
4(5x+1/3)^2+1=101

Question

factorizen
4(5x+1/3)^2+1=101

anonymous · Answer

subtract 1 from both sides
divide both sides by 4
take the square root, don't forget the $\pm$
then solve for $x$

anonymous · Answer

not sure what "factorizen" means, but it should be "solve for $x$"

tkhunny · Answer

4(5x+1/3)^2+1=101

Subtract 101

4(5x+1/3)^2 - 100 = 0

Factor out 4

4[(5x+1/3)^2 - 25] = 0

Recognize the Difference of Squares

4[5x+1/3 + 5][5x+1/3 - 5] = 0

Minor adjustments

4[5x + 16/3][5x - 14/3] = 0

Factor out the 5 if you wish.

20[x + 16/15][x - 14/15] = 0

anonymous · Answer

that will work as well, but i think it is more complicated

anonymous · Answer

you judge what you like for yourself

$$4(5x+\frac{1}{3})^2+1=101
\4(x+\frac{1}{3})^2=100\
(5x+\frac{1}{3})^2=25\
5x+\frac{1}{3}=5,5x+\frac{1}{3}=-5$$ etc