Question

I need help with the chain rule and implicit differentiation.
e^ycosx=1+sinxy

Answer 1

where are you stuck?

Answer 2

I am having a really hard time with the chain rule, period. Here's where I'm at:

Answer 3

\[\frac{ d }{ dx }(e ^{y})\times \frac{ d }{ dx }(cosx)=\frac{ d }{ dx }(1+sinxy)\]

Answer 4

stop there

Answer 5

remember that y is a function of x....so \[e^y\cos(x)\]

is the product of two functions of x...thus you need to use the product rule

Answer 6

right

Answer 7

the way you have it written above is not correct then

Answer 8

I'm having trouble with the equation tool on OpenStudy.

Answer 9

I'm going to have to fix my computer and come back. Sorry. I didn't mean to waste your time.

Answer 10

\[\frac{d}{dx}[e^y\cos(x)]=\frac{d}{dx}[e^y]\cdot\cos(x)+e^y\frac{d}{dx}\cdot[\cos(x)]\]