Question

factor completely

4x^2-16

Answer 1

can you factor out 4 first ?

Answer 2

\(4x^2= 4 \times x^2 \\ 16 = 4\times 4\)

Answer 3

4(x^2-4) ?

Answer 4

Yes

Answer 5

now since we know that \(4 = 2^2\)

we can use the relation
\(\large a^2-b^2 = (a+b)(a-b)\)

with a being 'x' and b being 2

Answer 6

@SolomonZelman no 4(x^2-4) is not the answer. I got it wrong

Answer 7

because we have still not completed the solution yet

Answer 8

Yeah, SAD !