Question

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Answer 1

Anyone willing to help me?

Answer 2

Do I need to take the inverse?

Answer 3

\[\tan \theta=-1=-\tan \frac{ \pi }{4 }=\tan \left( n \pi-\frac{ \pi }{4 } \right)=\tan \left( 4n-1 \right)\]
\[\theta=\left( 4n-1 \right)\frac{ \pi }{4 },where~n~is~an~integer.\]

Answer 4

In the second process, -tan pi/4, how did you get that?

Answer 5

\[\tan \frac{ \pi }{ 4 }=1\]

Answer 6

I have similar problem that goes sin(θ/2) = 1/2, how would this work out?

Answer 7

\[\sin \left( \frac{ \theta }{ 2 } \right)=\frac{ 1 }{ 2 }=\sin \left(2n \pi+ \frac{ \pi }{ 6 } \right),\sin \left(2n \pi+ \pi-\frac{ \pi }{ 6 } \right)\]
find \[\frac{ \theta }{ 2 }~ and~ then~ \theta \]

Answer 8

I'm lost, can you guide me?

Answer 9

I never recalled learning about some of this, it would help if you could guide me through it.

Answer 10

What I've got
θ = pi/3 + 4npi or θ =5pi/3 + 4npi