Evaluate the function at the indicated values.
f(x) = 6x2 + 2x − 12
f(x + 1)=
&
f(−x) =

Question

Evaluate the function at the indicated values. 
f(x) = 6x2 + 2x − 12
f(x + 1)=
  &
 f(−x)  =

tkhunny · Answer

$f(x) = 6x^{2} + 2x - 12$

$f(3) = 6(3)^{2} + 2(3) - 12$

$f(Dog) = 6(Dog)^{2} + 2(Dog) - 12$

$f(g(x)) = 6(g(x))^{2} + 2(g(x)) - 12$

Your turn.

$f(-x) = ??$

blaque678 · Answer

what that just really confused me

tkhunny · Answer

Whatever is in those parentheses on the left, substitute for the variable on the right - no matter what it is.  No confusion needed.  Just do the substitution.

blaque678 · Answer

the problem doesn't involve a 3 or anything with a dog or f(g(x)).That really wasn't any help at all. That just made your answer more crazy and doesn't seem like you know anything about this problem

tkhunny · Answer

It's called an example.  That's how ALL such functional notation works.

f(x) = 6x2 + 2x − 12

WHATEVER goes in here: f(Whatever)
ALSO goes whereever it appeared in the defintion: 6(Whatever)2 + 2(Whatever) − 12

So, what do you suppose you should do with f(-x)?
So, what do you suppose you should do with f(x+1)?