Question

FIND A POLYNOMIAL FUNCTION WITH REAL COEFFICIENTS THAT HAS THE GIVEN ZERO

Answer 1

In order to get those zeros, you know that x - (given zero) = 0. So you just plug in the zeros with the x, and multiply the equations (x + (given zero)) together for your answer. First, you get your x equations:
x - 2 = 0
x - (4 - 2i) = 0
However, those two are not your only given zeros. Because the "i" could be positive or negative, you have a third zero: 4 + 2i
x - (4 + 2i) = 0
Then you multiply your x equations together and set them equal to zero:
(x - 2)(x - 4 + 2i)(x - 4 -2i) = 0 <==== answer

Answer 2

I HAVE THIS : 4, -2i

Answer 3

(x+4)=0
(x-2i)=0

f(x)= (x+4)(x-2i)

now i'm stuck

Answer 4

just found this site had never used it,..taking college algebra