Geometry help (:
In the drawing below, the moment at which the aircraft’s wheels touch down on the runway is marked as W. The tower is located at T, and F is the point at which the airplane begins its final approach.The angle marked "angle of descent" and the angle marked "x" are complementary to each other. If the length from F to W is 26,000 feet, what is the altitude of your flight at the moment the plane begins its final descent?
So, I think the complementary angles have to do with Sine and Cosine.
So you basically need to find segment FT, right ?
Well, the angle of descent. I could find the angle given FT, yes.
idk, you gave me enough info. The only things I know is the triangle 90 and the hypotenuse.
maybe FT and FW are equal ?
The side can't be equal to the hypotenuse :P
I meant to say the 2 legs of the triangle.
FT anf WT
But how would I even find that :P
So you only know that WF (the hypotenuse) equals 26,000 and the right angle (on the bottom left of the triangle) ??
I can find the length of FT in terms of x.
@ranga -- @phi -- (Having technically difficulties here) I'm given an angle of depression of descent (36 degrees).
Oh you didn't say that bf
1) to find x, 90-36 2) find the remaining angle in the triangle (sum of angles in a triangle=180) 3) use law of sines. sinA / a = SinB / b
We haven't learned the laws of Sine...
OK, first tell me what x equals, ( and the remaining angle in a triangle ) . Also, I can teach you the law of sines right now, your are smart and the law is easy :)
"what is the altitude of your flight at the moment the plane begins its final descent?." So, we need to find TF, right?
I'll take you up on the Laws of Sine later, but right now I'm pressed for time (: We would use Cosine. Cos(54) = TF/26,000
^^^ you have the correct equation there. Solve for TF.
Law of sines. |dw:1396566369721:dw| you will know that angle W equals (also) 54. |dw:1396566476990:dw| can you solve for V ?
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