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Precalculus 12 Online
OpenStudy (anonymous):

How do you simplify cscx*secx-tanx?

OpenStudy (anonymous):

= ( 1 / cos x ) * ( cos x / sin x ) = ( 1 / sin x ) = csc x

OpenStudy (mathmale):

Re-writing csc x and sec x in terms of sin x (in the first case) and in terms of cos x (in the second) might help. Try it, please. @manguitar: Please justify your answer. Not sure I agree with what you're doing.

OpenStudy (anonymous):

No, I'm done. BTW It doesn't matter to me if you agree with what I'm doing.

OpenStudy (johnweldon1993):

Right...so \[\large \csc(x) = \frac{1}{\sin(x)}\] \[\large \sec(x) = \frac{1}{\cos(x)}\] \[\large \tan(x) = \frac{\sin(x)}{\cos(x)}\] Does that help at all?

OpenStudy (johnweldon1993):

So we have \[\large \frac{1}{\sin(x)}\times \frac{1}{\cos(x)} - \frac{\sin(x)}{\cos(x)}\]

OpenStudy (anonymous):

Yes, Thank you!

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