The number of passengers of terminal A, A(n) and terminal B, B(n), in the nth year are \(A(n)=2pq^n\) and \(B(n) = npq^2\), where p and q are positive constants. Show that the number of passenger of terminal B will not exceed that of terminal A in the future.
Sorry but can you explain constants i never get the parts of a equation right and no more than i know positive constants
Im good at equations just not the parts at all
Hmm, let's say, it is given that p=2000, q=495.
Sorry but im still dumbfounded let me get my friend
@kewlgeek555
Give me some probability no matter how hard i can do it in time but sometimes some equations just stupify me
(o-o) I don't think I am this advanced in Algebra, yet. (^_^;)
If number of passenger of terminal B will exceed that of terminal A, then \[npq^2>2pq^n\] for some positive integers n.
Yeah I can do this but it would probably just be quicker to get your local tutor service or a teacher to help. Try getting some of the higher level Helpers to get this by typing: @TheirName
LOL, I was tutoring when I overcame this question!
I can do this i learned it this year but the way i know 1 Number and 1 Exponent on different sides isnt enough for me to solve the... I know what it is called but i cant remember its a Equation but with larger smaller equal to equal to or less equal to or larger
Could you give me some numbers for some of the variables so that it would still work and still be solvable
and it would be \[npq^{2}\ge2pq ^{n}\]
Does not exceed it does not say cannot be equal to
"the number of passenger of terminal B will not exceed that of terminal A " B(n) <= A(n) :)
So if you could solve atleast one var on each side i can solve it
You mixed up the two function, perhaps :)
SO could you solve some vars please or make some that work
If I could solve it, I would not have posted it here :)
Ok then let me think
Im guessing that Npq stands for B(here) amd 2pq stands for A(here)
Well, \(B(n)=npq^2\) is a function in n.
JUST GO USE A INTERNET ALGEBRA CALCULATOR IM SORRY BUT I JUST CANT
Such calculators are not allowed in the exams...
(-_-) |____| \ \ [=] / / / (@_@)// / / / I RAGE QUIT THIS MATH!!!!
(-_-) /| |\ |____| [=] // (-_-) // / | \|\ / / / I JUST QUIT
I CANT DO IT
I TRIED AND FAILED BUT ATLEAST I TRIED
In one line A grows exponentially with n and B grows linearly with n. After a while, A will always be bigger than B \[ A(n)=C_1 q^n\\ B(n)=C_2 n \]
We have to suppose that q>1,
That's what I have told the girl I tutored. However, in case we must use a more "mathematical" way to do it, what is the possible approach to solve this problem?
Show her that if q>1, then \[ \lim_{n\to \infty}\frac{A(n)}{B(n)}=\infty \] Hence there is N, so n>N \[ \frac{A(n)}{B(n)}>1\\ A(n) > B(n) \]
I don't mind explaining the concept of limit to her, since she has not learnt it. Though, I bet she is not interested since it is out of syllabus. Thanks for your suggestions. :)
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