plzzzz helppp: what is a positive value of tan1/2x when sin x=0.8?
@mossyfish plz helpp
any1 plz help if u no
@Hero
\[sinx=0.8\] \[cosx=\pm \sqrt{(1-0.8^2)}=\pm0.6\] \[\tan(x/2)=1-cosx)/sinx\] Can you figure this out from here?
r u using the quadratic formula??
@mossyfish
Nope, trigonometric properties. What are your answer choices, btw?
what is the trigonometric property? canu write it?
choic are: 0.5 0.4 0.33 0.25
if sin(x)=8/10=4/5 then we can find cos(x) by using the right triangle associated with 4/5. Recall \[\cos^2(x/2)=\frac{1}{2}(1+\cos(x)) \text{ and } \sin^2(x/2)=\frac{1}{2}(1-\cos(x))\] so \[\tan(x/2)=\sqrt{\frac{1+\cos(x)}{1-\cos(x)}}\] so basically you are given sin(x)=4/5 just find what cos is off of your right triangle you drew for sin(x)=4/5
how did u gt sin(x)=8/10=4/5??
that is what is given
you are given sin(x)=8/10
no its n the problem is: what is a positive value of tan1/2x when sin x=0.8?
right sin(x)=8/10
0.8 is same at 8/10?
of course
its nt 4/5?
8/10=4/5
it is called reducing a fraction
.8=4/5
ohh I see
ok now I don't gt where ur gttin the rest frm?
trig identities
oh now im gona use these identities to solve the problem?
half angle identities
ok how do I know which identity im gona use for this problem?
well the key is noticing it is asking for tan(x/2) that looks like half an angle there because of the over 2 part so we know to use the half angle identity
so we gona use the tan(x/2)=1+cos x/1-cos x?
@myininaya
no you can use \[\tan(x/2)=\sqrt{\frac{1-\cos(x)}{1+\cos(x)}}\]
so now I need to plug in?
@myininaya
after you find the value for cos
you know sin(x)=4/5
so what is cos(x)=
ugh can we plz go thro every step? how did we find the value of cos?
try to draw a right triangle for sin(x)=4/5 then find the adjacent side brb
ok waitng
@mossyfish
I think @myininaya is doing a fine job helping you :) Tag me in other questions you might need help with.
she is but she said brb and I thought maybr u could help me for now...
ik shes helping me good
Okay well, continuing from where I was from.. When cosx=-0.6 tan(x/2)=(1+06)/0.8-2 When cosx=.6 tan(x/2)=(1-0.6)/0.8 which equals...?
u both are doin 2 diff things and its confusing me I need u to plz tel step by step if u culd?
Yeah this is why @myininaya should help you... We both have different methods of solving this, jumping back and forth between us isn't going to help you :( Good luck!
ok fine thnks
Have you drew a right triangle and use the sin(x)=4/5 to label the triangle yet?
yes
then find the missing side
which is what?
do I use the pathagreom theorem?
|dw:1396635164409:dw| yep it is a right triangle so use that theorem
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