Question

.

Answer 1

ignore the work on the side haha

Answer 2

i'm not sure if it's B or C

Answer 3

E

Answer 4

\(x^2+4\) is an irreducible quadratic, so you need a linear factor on the numerator.

and \(x^2-1\) factors out more to \((x-1)(x+1)\) It's a difference of squares.

Answer 5

and \((x+7)^2\) is a repeated irreducible linear factor, so you need to include both \[\frac{A}{x+7}\text{and } \frac{B}{(x+7)^2} \text{terms} \]

Answer 6

Thank you! That makes much more sense to me now.

Answer 7

:)